1.

Discuss the maximum possible number of positive and negative roots of the polynomial equation 9x9 – 4x8 + 4x7 – 3x6 + 2x5 + x3 + 7x2 + 7x + 2 = 0.

Answer»

P(x) = 9x9 – 4x8 + 4x7 – 3x6 + 2x5 + x3 + 7x2 + 7x + 2

The number of sign changes in P(x) is 4. 

∴ P(x) has atmost 4 positive roots. 

P(-x) = -9x9 – 4x8 - 4x7 – 3x6 - 2x5 - x3 + 7x2 - 7x + 2

The number of sign changes in P(-x) is 3. 

Therefore, P(x) has atmost 3 negative roots.



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