Saved Bookmarks
| 1. |
Discuss the maximum possible number of positive and negative roots of the polynomial equation 9x9 – 4x8 + 4x7 – 3x6 + 2x5 + x3 + 7x2 + 7x + 2 = 0. |
|
Answer» P(x) = 9x9 – 4x8 + 4x7 – 3x6 + 2x5 + x3 + 7x2 + 7x + 2 The number of sign changes in P(x) is 4. ∴ P(x) has atmost 4 positive roots. P(-x) = -9x9 – 4x8 - 4x7 – 3x6 - 2x5 - x3 + 7x2 - 7x + 2 The number of sign changes in P(-x) is 3. Therefore, P(x) has atmost 3 negative roots. |
|