

InterviewSolution
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Distinguish between the following pairs of compounds using the test given within brackets: 1. Iron (II) sulphate and iron(III) sulphate (using ammonium hydroxide) 2. A lead salt and a zinc salt (using excess ammonium hydroxide) 3. Sodium nitrate and sodium sulphite (using dilute sulphuric acid) 4. Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution) 5. Ethane and ethene (using alkaline potassium permanganate solution. |
Answer» 1. Iron II sulphate: Gives dirty green ppt with ammonium hydroxide insoluble in excess. Iron III sulphate: Gives reddish brown ppt with ammonium hydroxide insoluble in excess. 2. Lead salt: Gives white ppt with ammonium hydroxide which is insoluble in excess. Zinc salt: Gives gelatenous white ppt which is soluble in excess ammonium hydroxide. 3. Sodium nitrate: Colourless vapours of nitric acid which condenses to form nitric acid. Sodium sulphite: Colourless, gas with smell of burning sulphur, acidic in nature that is sulphur di oxide is released. 4. With dil. HCl, BaCl2 gives no ppt with dil. H2SO4, BaCl2 gives a white insoluble ppt of BaSO4. 5. With ethane, purple colour of potassium permanganate remains unfaded with ethene the purple colour gets decolourised. |
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