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Draw graphs a to t, v to t and x to tfor the object falling freely.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E01_027_S01.png" width="80%"/> <br/> For object <a href="https://interviewquestions.tuteehub.com/tag/falling-983241" style="font-weight:bold;" target="_blank" title="Click to know more about FALLING">FALLING</a> freely, <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> is constant and equation to negative g. Thus, graph (a) shows the change in acceleration with respect to time `(a to t ).` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E01_027_S02.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/velcity-3258504" style="font-weight:bold;" target="_blank" title="Click to know more about VELCITY">VELCITY</a> of object falling freely, `v =- g t.` THus, graph (b) is obtained for `v to t.` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E01_027_S03.png" width="80%"/><br/> For object falling freely, `h = 1/2 g t ^(2).` Thus graph (c) is obtained for `x to t.`</body></html>


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