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Draw the P-T and V-T diagrams for an isobaric process of expansion, corresponding to n moles of an ideal gas at a pressure P_(0),from V_(0) to 2V_(0). |
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Answer» SOLUTION :For the graph of P versus T the variation is a straight line normal to the PRESSURE axis, the temperature varying from `T_(1)`to `T_(2)`as shown figure. From the gas equation PV = nRT we have, `V = ((NR)/(P_(0)))T or V prop T` At `V=V_(0) , T_(1) =(P_(0)V_(0))/(nR) and " at " V=2V_(0), T_(2) =(2P_(0) V_(0))/(nR)` From the graph of V versus T, the equation `V=((nR)/(P_(0)))T or V = kT` shows that the volume variesdirectly, as the temperature (Charles. law). So, the graph is a straight line inclined to the (V-T) axis, and passing through the ORIGIN (when produced) as shown in figure. |
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