1.

Draw the P-T and V-T diagrams for an isobaric process of expansion, corresponding to n moles of an ideal gas at a pressure P_(0),from V_(0) to 2V_(0).

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For the graph of P versus T the variation is a straight line normal to the <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> axis, the temperature varying from `T_(1)`to `T_(2)`as shown figure.<br/> From the gas equation PV = nRT<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C13_SLV_033_S01.png" width="80%"/> <br/> we have, `V = ((<a href="https://interviewquestions.tuteehub.com/tag/nr-581903" style="font-weight:bold;" target="_blank" title="Click to know more about NR">NR</a>)/(P_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)))T or V prop T` <br/> At `V=V_(0) , T_(1) =(P_(0)V_(0))/(nR) and " at " V=2V_(0), T_(2) =(2P_(0) V_(0))/(nR)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C13_SLV_033_S02.png" width="80%"/> <br/> From the graph of V versus T, the equation `V=((nR)/(P_(0)))T or V = kT` shows that the volume variesdirectly, as the temperature (Charles. law). So, the graph is a straight line inclined to the (V-T) axis, and passing through the <a href="https://interviewquestions.tuteehub.com/tag/origin-1139399" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGIN">ORIGIN</a> (when produced) as shown in figure.</body></html>


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