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During electrolysis of aqueous `CuBr_(2)` using `Pt` electrode,A. `Br_(2)(g)` is evolved at anodeB. `Cu(s)` is deposited at cathdoeC. `Br_(2)(g)` is evolved at anode and `H_(2)(g)` at cathodeD. `H_(2)(g)` is evolved at anode |
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Answer» Correct Answer - a,b Aqueous `CuBr_(2):` At cathode `:(sqrt())Cu^(2+)+2e^(-)rarr Cu,` `E^(c-)._(Cu^(2+)|Cu)=+0.34V` `(X)2H_(2)O+2e^(-) rarr H_(2)+2overset(c-)(O)H,` ltbr. `E^(c-)._(H_(2)O|H_(2))=-0.83V` At anode `:(sqrt())2Br^(c-)rarr Br_(2)+2e^(-),` `E^(c-)._(Br^(c-)|Br_(2))=-1.09V` `(X)2H_(2)Orarr O_(2)+4H^(o+)+2e^(-), ` `E^(c-)._(H_(2)O|H_(2))=-1.23V` |
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