InterviewSolution
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InterviewSolution
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`E^(c-)` of some elements are given as `:` `{:(I_(2)+2e^(-)rarr 2I^(c-),,,,E^(c-)=0.54V),(MnO_(4)^(c-)+8H^(o+)+5e^(-)rarr Mn^(2+)+4H_(2)O,,,,E^(c-)=1.52V),(Fe^(3+)+e^(-)rarr Fe^(2+),,,,E^(c-)=0.77V),(Sn^(4+)+2e^(-)rarr Sn^(2+),,,,E^(c-)=0.1V):}` `a.` Select the stronges reductant and weakes oxidant among these elements. `b.` Select the weakest reductant and strongest oxidant among these elements. |
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Answer» (a) More the `E_(OP)^(@)` more is the tendency for oxidation. Therefore, since maximum `E_(OP)^(@)` stands for: `{:(Sn^(2+)rarrSn^(4+)+2e^(-),,E_(OP)^(@)=-0.1V),( :."Strongest reductant",:,Sn^(2+)),("and weakest oxidant",:,Sn^(4+)):}` (b) More `+ve` is `E_(RP)^(@)` more is the tendency for reduction. Therefore, since maximum `E_(RP)^(@)` stands for: `{:(MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O,,E_(RP)^(@)=+1.52V),( :."Strongest oxidant",:,MnO_(4)^(-)),("and weakest reductant",:,Mn^(2+)):}` Note-Stronger is oxidant, weaker is its conjugate reducant and vice-verse. (c) For (i) `E_(Ceff) = E_(OP_(Fe^(2+)//Fe^(3+))) +E_(RP_(Sn^(4+)//Sn^(2+))) =- 0.77 +0.1` `Fe^(2+)` oxidizes and `Sn^(4+)` reduces in change. `:. E_(Ceff) = E_(OP_(Fe^(2+)//Fe^(3+))) +E_(RP_(Sn^(4+)//Sn^(2+))) =- 0.77 +0.1 =- 0.67 V` `E_(Cell)` is negative. `:.` (i) Is non-spontaneous change. For (ii) `E_(Cell) = E_(OP_(Fe^(2+)//Fe^(3+)))E_(RP_(I_(2)//I^(-))) =- 0.77 +0.54 =- 0.23 V` `:.` (ii) reaction is non-spontaneous change. For (iii) `:. E_(Ceff) = E_(OP_(I^(-)//I_(2))) +E_(RP_(Sn^(4+)//Sn^(2+))) =- 0.54 +0.1 =- 0.44V` `:.` (iii) Reaction is non-spontaneous change. For (iv) `E_(Cell) = E_(OP_(Sn^(2+)//Sn^(4+)))+E_(RP_(I_(2))//I^(-)) =- 0.1 +0.54 = +0.44V` (iv) Reaction is spontaneous change. |
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