`E^(@)` for the electrochemical cell `Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+) 1 M (aq.)|Cu(s)` is 1.10 V at `25^(@)C`. The equilibrium constant for the cell reaction, `Zn(s) +Cu^(2+) (aq.) hArr Zn^(2+) (aq.)+Cu(s)` Will be :A. `10^(-37)`B. `10^(37)`C. `10^(-39)`D. `10^(39)`

`E^(@)` for the electrochemical cell `Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+)

1.	`E^(@)` for the electrochemical cell `Zn(s)\|Zn^(2+) 1 M (Aq.)\|\|Cu^(2+) 1 M (aq.)\|Cu(s)` is 1.10 V at `25^(@)C`. The equilibrium constant for the cell reaction, `Zn(s) +Cu^(2+) (aq.) hArr Zn^(2+) (aq.)+Cu(s)` Will be :A. `10^(-37)`B. `10^(37)`C. `10^(-39)`D. `10^(39)`
Answer» Correct Answer - B K = antilog `[(nE^(@))/0.0591]` = antilog `[(2xx1.10)/0.0591]=1.67xx10^(37)`

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`E^(@)` for the electrochemical cell `Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+) 1 M (aq.)|Cu(s)` is 1.10 V at `25^(@)C`. The equilibrium constant for the cell reaction, `Zn(s) +Cu^(2+) (aq.) hArr Zn^(2+) (aq.)+Cu(s)` Will be :A. `10^(-37)`B. `10^(37)`C. `10^(-39)`D. `10^(39)`

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