Each of A, B, C and D need a umique time to do a certain work. A can do the work in x days and B can do the work in 2x days. A started the work and do it for 22 2/9 days then he is replaced by B and B completed remaining work in same time as C and D together can complete the whole work. The ratio of the efficiency of C and D is 4: 5. If C and D work for alternative days starting form C then they can do the total work in 44 1/2 days.

Each of A, B, C and D need a umique time to do a certain work. A can

1.	Each of A, B, C and D need a umique time to do a certain work. A can do the work in x days and B can do the work in 2x days. A started the work and do it for 22 2/9 days then he is replaced by B and B completed remaining work in same time as C and D together can complete the whole work. The ratio of the efficiency of C and D is 4: 5. If C and D work for alternative days starting form C then they can do the total work in 44 1/2 days.
Answer» 66(2/3) 33(1/3) 16(2/3) 14(2/7) Solution :Let E do work in 4x days Let F do work in 5x days ` 24/(5x) + 24 /(4x) + 20 /(100/3) + 20/(200/3) = 1` ` 24 = (9)/(20x) +( 60)/(100) +( 60)/(200) + 1` `(24xx9)/(20x)= 1/10` `x = 108` Together E and F can do work in `= (4xx108 xx 5 xx108)/(9xx 108)` `= 240` days Required difference `= 240/(4xx108 )-240 (5xx 108)` `240/108 xx1/20 = 1/9`