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Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per sound will be heard by A and B

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/apparent-363672" style="font-weight:bold;" target="_blank" title="Click to know more about APPARENT">APPARENT</a> frequency , n. ` (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> + u_(0))/(c- u_(5)) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> n`<br/>The distance between A and B is dacreasing . So , the velocity of the listener ` u_(0) ` and that of the source ` u_(s) ` , are both positive<br/>When A is the listener, velocity of the listener, ` u_(0) = u` , <br/> Velocity of the source ` B , u_(s) = 0 `<br/> So, ` n_(A) = (c + u)/(c) xx n `<br/> Evidently , ` n_(A) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> n`<br/> ` thereforeNumber of beats per socond<br/> ` = n_(A) - n = ((c + u)/(c) - 1) xx n = u/c n ` .</body></html>


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