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Electrolysis is an impotant technique for extraction of metals, and each of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potential follow the order given below: `Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+)` `H_(3)O gt Cu^(2+) gt H_(2)^(2+) gt Ag^(+) gt Au^(3+)`. For some anions the discharge potentials:- `SO_(4)^(2-) gt BO_(3)^(-) OH^(-) gt Br^(-) gt I^(-)` When aqueous solution of cupric bromide is electrolysed, the product obtained at cathode will beA. CuB. `H_(2)`C. `Br_(2)`D. `O_(2)`

Answer» Correct Answer - d


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