Equivalent conductivity at infinite dilution for sodium potassium oxalate `(COO^(-))_(2)Na^(+)K^(+)` will be [given, molar conductivities of oxalate, `K^+ and Na^(+)` ions at infinite dilution are 148.2, 50.1, 73.5 S `cm^(2)mol^(-1)`, respectively]A. `271.8cm^(2)eq^(-1)`B. `67.95S" "cm^(2)eq^(-1)`C. `543.6S" "cm^(2)eq^(-1)`D. `135.9S" "cm^(2)eq^(-1)`

Equivalent conductivity at infinite dilution for sodium potassium oxal

1.	Equivalent conductivity at infinite dilution for sodium potassium oxalate `(COO^(-))_(2)Na^(+)K^(+)` will be [given, molar conductivities of oxalate, `K^+ and Na^(+)` ions at infinite dilution are 148.2, 50.1, 73.5 S `cm^(2)mol^(-1)`, respectively]A. `271.8cm^(2)eq^(-1)`B. `67.95S" "cm^(2)eq^(-1)`C. `543.6S" "cm^(2)eq^(-1)`D. `135.9S" "cm^(2)eq^(-1)`
Answer» Correct Answer - D `lamda_(M)^(oo)=lamda_(M)^(oo)("Oxalate")+lamda_(M)^(oo)(Na^(+))+lamda_(M)^(oo)(k^(+))` `lamda_(M)^(oo)=(148.2+50.1+73.5)S" "cm^(2)mol^(-1)` `lamda_(M)^(oo)=271.8S" "cm^(2)mol^(-1)` `thereforelamda_(Eq)^(oo)=(271.8)/(2)=135.9S" "cm^(2)eq^(-1)(lamda_(eq)^(oo)=(lamda_(M)^(oo))/("n. factor"))`

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