InterviewSolution
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InterviewSolution
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Equivalent conductivity at infinite dilution for sodium potassium oxalate, `(COO^(-))_(2)Na^(+)K^(+)`, will be (given, molar conductivities of oxalate, `K^(+) and Na^(+)` ions at infinite diluton are `148.2,50.1,73.5" S "cm^(2)mol^(-1)` respectively).A. `271.8" S "cm^(2)eq^(-1)`B. `67.96" S "cm^(2)eq^(-1)`C. `543.6" S "cm^(2)eq^(-1)`D. `135.9" S "cm^(2)eq^(-1)`. |
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Answer» Correct Answer - D `wedge_(m)^(@)` (Sod. Pot. Oxalate)`=lamda_(m)^(@)(Na^(+))+lamda_(m)^(@)(K^(+))+lamda^(2)`(oxalate) `=(50.1+73.5+148.2)" S "cm^(2)mol^(-1)` `=271.8" S "cm^(2)mol^(-1)` `wedge_(eq)^(@)=(wedge_(m)^(@))/("Total chrge on cations or anions (n factor)")` `=(271.8)/(2)=135.9" S "cm^(2)eq^(-1)`. |
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