Equivalent weight of `H_(3)PO_(2)` in a reaction is found to be half of its molecular weight. It can be due to itsA. oxidation to `H_(3)PO_(3)`B. reaction of two `H^(+)` ionsC. oxidation to `H_(3)PO_(4)`D. reduction to `PH_(3)`

Equivalent weight of `H_(3)PO_(2)` in a reaction is found to be half o

1.	Equivalent weight of `H_(3)PO_(2)` in a reaction is found to be half of its molecular weight. It can be due to itsA. oxidation to `H_(3)PO_(3)`B. reaction of two `H^(+)` ionsC. oxidation to `H_(3)PO_(4)`D. reduction to `PH_(3)`
Answer» Correct Answer - A (`a`) It is monobasic acid, hence only one `H^(+)` can be neutralised `E=(M)/(1)` (`b`) `underset(+1)underset(uarr)(H_(3)PO_(2)) rarr underset(+3)underset(uarr)(H_(3)PO_(3))` `E=(M)/(2)` (`c`) `underset(+1)underset(uarr)(H_(3)PO_(2)) rarr underset(+5)underset(uarr)(H_(3)PO_(4))` `E=(M)/(4)` (`d`) `underset(+1)underset(uarr)(H_(3)PO_(2)) rarr underset(-3)underset(uarr)(PH_(3))` `E=(M)/(4)`

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Equivalent weight of `H_(3)PO_(2)` in a reaction is found to be half of its molecular weight. It can be due to itsA. oxidation to `H_(3)PO_(3)`B. reaction of two `H^(+)` ionsC. oxidation to `H_(3)PO_(4)`D. reduction to `PH_(3)`

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