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| 1. |
Estimate the mean free path for a water molecule in water vapour at 373 K. |
| Answer» <html><body><p></p>Solution :The number density (<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>) is inversely proportional to absolute <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>. <br/> `n alpha 1/T <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> (n_(373))/(n_(273))-(273)/(373)` <br/> `rArr n_(373)=n_(273) xx (273)/(373)` <br/> `n_(373)=2.7 xx 10^(25) xx (273)/(373)=2 xx 10^(25)m^(-3)` <br/> Given `d=2 xx 10^(-10)m` <br/> Hence, mean free path `lambda=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a> pi d^2 n)` <br/> `=(1)/(sqrt2 xx 3.14 xx (2 xx 10^(-10))^(2) xx 2 xx 10^(25))=<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> xx 10^(-7)m`</body></html> | |