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Estimate the mean free path for a water molecule in water vapour at 373 K. |
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Answer» Solution :The number density (N) is inversely proportional to absolute TEMPERATURE. `n alpha 1/T RARR (n_(373))/(n_(273))-(273)/(373)` `rArr n_(373)=n_(273) xx (273)/(373)` `n_(373)=2.7 xx 10^(25) xx (273)/(373)=2 xx 10^(25)m^(-3)` Given `d=2 xx 10^(-10)m` Hence, mean free path `lambda=(1)/(SQRT2 pi d^2 n)` `=(1)/(sqrt2 xx 3.14 xx (2 xx 10^(-10))^(2) xx 2 xx 10^(25))=4 xx 10^(-7)m` |
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