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1. |
Evaluate `int sin(logx)dx`. |
Answer» Let `log x =t.` Then, `x=e^(t)impliesdx=e^(t)dt` ` :. I =int sin(logx)dx` `=int sin t e^(t) dt` `=(e^(t))/(2)(sint-cost)+C` Hence, `int sin(logx)dx=(x)/(2) [sin(logx)-cos(logx)]+C` |
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