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Evaluate the integral: ∫sec4 x dx |
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Answer» It is given that ∫ sec4 x dx We can write it as = ∫sec2 x sec2 x dx So we get = ∫ (1 + tan2 x) sec2 x dx Take tan x = t By differentiation we get sec2 x dx = dt It can be written as = ∫(1 + t2) dt By integrating w.r.t. t = t + t3/3 + c By substituting the value of t = tan x + tan3 x/3 + c |
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