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Excess pressure can be `(2T//R)` forA. spherical dropB. spherical meniscusC. clindrical bubble in airD. spherical bubble in water |
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Answer» Correct Answer - A::B::C::D i. Excess pressure inside a spherical liquid drop `(2T)/(R)` because there is only one free surface here (ii). In case of spherical meniscus of radius of curvature R, also excess pressure `=(2T)/(R)` because again there is only one free surface. (iii). Excess pressure inside a cylindrical drop of radius `R=(T)/(R)`, hence, for a culindrical bubble in air, excess pressure is `(2T)/(R)` because there exists two free surface `=(T)/(R)` in this case (iv). for a spherical bubble in water, excess pressure `=(T)/(R)`, as there is only one free surface. Hence, all the four optional are correct. |
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