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Explain in detail the idea of weightlessness using lift as an example. |
Answer» <html><body><p></p>Solution :When a man is standing in the elevator, there are two forces acting on him. <br/>1. Gravitational force which acts downward. If we take the vertical direction as <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> y direction, the gravitational force acting on the man is `vecF_G =- <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> hatj` <br/>The normal force exerted by floor.on the man which acts vertically upward, `vecN = Nhatj`Weightlessness of freely falling bodies: Freely falling objects <a href="https://interviewquestions.tuteehub.com/tag/experience-25558" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIENCE">EXPERIENCE</a> only gravitational force. As they fall freely, they are not in <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> with any surface (by neglecting air friction). The normal force acting on the object is zero. The downward acceleration is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the acceleration due to the gravity of the i.e., (a = g) . Newton.s 2nd law acting on the man `N= mg (g - a) [ because a = g ] N= 0`</body></html> | |