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Explain in detail the kinetic interpretation of temperature . |
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Answer» Solution :We KNOW that , `P=1/3N/V mbar(v^2)` `PV=1/3Nmbar(v^2)` Comparing the equation (1) with ideal gas equation PV = NkT, `NkT=1/3Nmbar(v^2)` `kT =1/3mbar(v^2)""...(2)` MULTIPLY the above equation by 3/2 on both sides, `3/2kT = 1/2 mbar(v^2)""....(3)` R.H.S of the equation (3) is called average kinetic energy of a single molecule `bar(KE)` . The average kinetic energy per molecule `bar(KE)= in =3/2kT ""...(4)` It is implied from equation (3) that the temperature of a gas isa measure of the average translational kinetic energy per molecule of the gas. |
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