InterviewSolution
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InterviewSolution
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Explain the nature of the covalent bond using the bond formation in `CH_(3)Cl`. |
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Answer» `CH_(3)Cl` is methyl chloride (or chloromethane). It is made up of one carbon atom, three hydrogen atoms and one chlorine atom. Carbon atom has 4 outermost electron (or valence electrons), each hydrogen atom has 1 outermost electron, and chlorine atom has 7 valence electrons. carbon atom shares its 4 valence electrons with three hydrogen atoms and one chlorine atom to form `CH_(3)Cl` as shown below. `underset("Hydrogen atom")(3H+)+underset("Carbon atom")(underset(.)overset(.)(*C*)+underset("Chlorine atom")(underset(..)overset(..)(*C: )tounderset("Electron-dot structure of "CH_(3)Cl)(Hunderset(H)overset(H)(underset(. .)overset(. .)( : C : )underset(* *)overset(* *)(Cl: )` or `H-underset(H)underset(|)overset(H)overset(|)(C)-Cl` We can see from the above electron-dot structure of `CH_(3)Cl` that there are four pairs of shared electrons between carbon and other atoms. Eac pair of shared electrons constitues one single covalent bond. So, `CH_(3)Cl` has four single covalent bonds. Please note that each atom in `CH_(3)Cl` has a noble gas electron arrangement (of 2 or 8 electrons in the outermost shell). |
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