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Explain the process of γ-decay in detail with a suitable example. |
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Answer» γ-decay: i. γ-Radiation is always accompanied with α and β decay processes. ii. During γ-radiation, the daughter nucleus is left in energetically excited state which decays to the ground state of product with emission of γ-rays. For example, \(^{238}_{92}U\) \(\longrightarrow\) \(^{234}_{90}Th\) + \(^{4}_{2}He\) + γ iii. \(^{238}_{92}U\) emits α-particles of two different energies, 4.147 MeV (23%) and 4.195 MeV (77%). iv. When α-particles of energy 4.147 MeV are emitted, 234Th is left in an excited state which de-excites to the ground state with emission of γ-ray photons with energy 0.0048 MeV. |
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