InterviewSolution
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Explain the use of a resistor in series with a Zener diode. |
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Answer» The I-V characteristics in the breakdown region of a Zener diode is almost vertical. That is, the current IZ can rapidly increase at constant VZ. To prevent damage due to excessive heating, the Zener current should not exceed the rated maximum current, IZM. Hence, a current-limiting resistor Rs is connected in series with the diode IZ and the power dissipated in the Zener diode will be large for IL = 0 (no-load condition) or when IL is less than the rated maximum (when Rs is small and RL is large). The currentlimiting resistor RS is so chosen that the Zener current does not exceed the rated maximum reverse current, IZM when there is no load or when the load is very high. The rated maximum power of a Zener diode is PZM = IZM = VZ At no-load condition, the current through Rs Z = IZM and the voltage drop across it is V – VZ, where V is the unregulated source voltage. The diode current will be maximum when V is maxi-mum at Vmax and I = IZM. Then, the minimum value of the series resistance should be Rs, min = \(\cfrac{V_{max}−V_Z}{I_{ZM}}\) A Zener diode is operated in the breakdown region. There is a minimum Zener current, IZ (min), that places the desired operating point in the breakdown region. There is a maximum Zener current, IZM, at which the power dissipation drives the junction temperature to the maximum allowed. Beyond that current the diode can be damaged. Hence, the supply voltage must be greater than Vz and the current-limiting resistor must limit the diode current to less than the rated maximum, IZM. |
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