Explain the variation of 'g' with altitude.

1.	Explain the variation of 'g' with altitude.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Variation of g with altitude: <br/> Consider an object of mass m at a height h from the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of the Earth. Acceleration experienced by the object due to Earth is <br/> `g' = (GM)/((R_(E) + h)^(2))` <br/> `R_(E) to` Radius of Earth <br/> `g' = (GM)/(R_(E)^(2)(1 + h/(R_E))^(2)) = (GM)/(R_E^2) (1 + h/(R_E))^(-2)` <br/> If `h < < R_(E)` <br/> We can use Binomial expansion. Taking the terms <a href="https://interviewquestions.tuteehub.com/tag/upto-1440527" style="font-weight:bold;" target="_blank" title="Click to know more about UPTO">UPTO</a> first order <br/> `g' = (GM)/(R_E^2) (1-2h/(R_E)) = g(1-2 h/(R_E))` <br/> We find <a href="https://interviewquestions.tuteehub.com/tag/tat-1239509" style="font-weight:bold;" target="_blank" title="Click to know more about TAT">TAT</a> `g' < g`. This means that as altitude h increases, the acceleration due to gravity g decreases. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C06_E03_009_S01.png" width="80%"/>.</body></html>

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