1.

Feed of a reactor has 0.75 mass fraction of O2 and some SO2, if the product rate is 1000 Kg/hr then what is the rate of SO2 in the feed?(a) 100 Kg/hr(b) 250 Kg/hr(c) 750 Kg/hr(d) 1000 Kg/hrThis question was posed to me during an online exam.The origin of the question is Multiple Component Systems topic in division Introduction to Material Balances of Basic Chemical Engineering

Answer»

Correct option is (B) 250 Kg/hr

The BEST explanation: Feed rate = Product rate = 1000 Kg/hr, => Rate of SO2 = (1 – 0.75)*1000 = 250 Kg/hr.



Discussion

No Comment Found

Related InterviewSolutions