Fig. 2 (b). 12` shows thae distance (S) -time (t) graphs of two trains, which start moving simultaneously in the same direetion. From the graphs, find: . (a) How much (B) is ahead of (A) when motion starts (b) What is the speed of (B) ? ( c) What and where (A) will catch (B) ? ` (d) What is the differnce in speeds of (A) and (B) ? lt

Fig. 2 (b). 12` shows thae distance (S) -time (t) graphs of two trains

1.	Fig. 2 (b). 12` shows thae distance (S) -time (t) graphs of two trains, which start moving simultaneously in the same direetion. From the graphs, find: . (a) How much (B) is ahead of (A) when motion starts (b) What is the speed of (B) ? ( c) What and where (A) will catch (B) ? ` (d) What is the differnce in speeds of (A) and (B) ? lt
Answer» (a) When motion starts, (B) is ahead of (A) by the distance `OC= 80 km`. (b) Speed of `B =(DE)/(CE) =(120-80)/(2-0) =20 km h^(-1)` (c ) Since the two graphs at point `D, so A` woll catch (B) after 2 ours and at a destance of `120 km` from the origh. (d) Speed of `A =(DF)/(FO) =(120-0)/(2-0) =60 km h^(-1)` Differnce in speed `60 -20 40 km h^(-1)`.

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