Fig. shows a surface XY separating two transparent media, medium 1 and medium 2. Lines ab and cd represent wavefronts of a light wave travelling in medium 1 and incident on XY. Line ef and gh represent wavefront of the light wave in medium 2 after rafraciton. The phase of the ligth wave at c, d, e, and f are `phi_(c)`, phi_(d), `phi_(e)` and `phi_(f)`, respectively. It is given that `phi_(c ) != phi_(f)`. ThenA. `phi_(c )` cannot be equal to `phi_(d)`B. `phi_(d )` can be equal to `phi_(d)`C. `phi_(d ) - phi_(f)` is equal to `phi_(c) - phi_(e)`D. `phi_(d ) - phi_(c)` is not equal to `phi_(f) - phi_(e)`

Fig. shows a surface XY separating two transparent media, medium 1 and

1.	Fig. shows a surface XY separating two transparent media, medium 1 and medium 2. Lines ab and cd represent wavefronts of a light wave travelling in medium 1 and incident on XY. Line ef and gh represent wavefront of the light wave in medium 2 after rafraciton. The phase of the ligth wave at c, d, e, and f are `phi_(c)`, phi_(d), `phi_(e)` and `phi_(f)`, respectively. It is given that `phi_(c ) != phi_(f)`. ThenA. `phi_(c )` cannot be equal to `phi_(d)`B. `phi_(d )` can be equal to `phi_(d)`C. `phi_(d ) - phi_(f)` is equal to `phi_(c) - phi_(e)`D. `phi_(d ) - phi_(c)` is not equal to `phi_(f) - phi_(e)`
Answer» Correct Answer - c All points on a wavefront are at the same phase `phi_(d) = phi_(c)` and `phi_(f) = phi_(e)` `phi_(d) - phi_(f) = phi_(c) - phi_(e)` Hence, the correct option is (c).

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