1.

Fig. shows the position-time graph of a particle of mass 0.04 kg. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the particles? What is the magnitude of each impulse?

Answer»

This graph can be of a ball rebounding between two walls situated at position 0 cm and 2 cm. The ball is rebounding from one wall to another, time and again every 2 sec. with uniform velocity.

Here, velocity = {displacement}/{time}

= {2}/{100 x 2} = 0.01 ms-1

Initial momentum = mu = 0.04 x 0.01 = 4 x 10-4 kg ms-1

Final momentum = mv = 0.04 x (-0.01)

= -4 x 10-4 kg ms-1

Magnitude of impulse = change in momentum

= (4 x 10-4) - (-4 x 10-4)

= 8 x 10-4 kg ms-1

Time between two consecutive impulses is 2 s, i.e., the ball receives an impulse every two seconds.


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