Figure below shows two paths that may be taken by a gas to go from state A to a state C. In process AB, 400 Jof heat is added to the system and in proces BC, 100 J of heat isadded to the system. The heat absorbed by the system in the process AC will be

Figure below shows two paths that may be taken by a gas to go from sta

1.	Figure below shows two paths that may be taken by a gas to go from state A to a state C. In process AB, 400 Jof heat is added to the system and in proces BC, 100 J of heat isadded to the system. The heat absorbed by the system in the process AC will be
Answer» 460 J 300 J 380 J 500 J Solution :As initial and final points are same so `Delta U_(ABC) = Delta U_(AC)` AB is isochoric PROCESS. `Delta W_(AB) = 0` `Delta Q_(AB) = Delta U_(AB) = 400 J` B is isobaric process. `Delta Q_(BC) = Delta U_(BC) + Delta W_(BC)` `100 = Delta U_(BC) + 6 xx 10^(4)` `(4 xx 10^(-3) - 2 xx 10^(-3))` `100 = Delta U_(BC) + 12 xx 10` `Delta U_(BC) = 100 - 120 = -20 J` As, `Delta U_(ABC) = Delta U_(AC)` `Delta U_(AB) + Delta U_(BC) = Delta Q_(AC) - Delta W_(AC)` `400 - 20 = Delta Q_(AC) - (2 xx 10^(4) xx 2 xx 10^(-3) + (1)/(2) xx 2 xx 10^(-3) xx 4 xx 10^(4))` `380 = Delta Q_(AC) - (40 + 40), Delta Q_(AC) = 380 + 80 = 460 J`