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Figure below shows two paths that may be taken by a gas to go from state A to a state C. In process AB, 400 Jof heat is added to the system and in proces BC, 100 J of heat isadded to the system. The heat absorbed by the system in the process AC will be

Answer» <html><body><p>460 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>300 J<br/><a href="https://interviewquestions.tuteehub.com/tag/380-310180" style="font-weight:bold;" target="_blank" title="Click to know more about 380">380</a> J<br/>500 J</p>Solution :As initial and final points are same so `Delta U_(ABC) = Delta U_(AC)` <br/> AB is isochoric <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a>. `Delta W_(AB) = 0` <br/> `Delta Q_(AB) = Delta U_(AB) = 400 J` <br/> B is isobaric process. <br/> `Delta Q_(BC) = Delta U_(BC) + Delta W_(BC)` <br/> `100 = Delta U_(BC) + <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 10^(4)` <br/> `(4 xx 10^(-3) - 2 xx 10^(-3))` <br/> `100 = Delta U_(BC) + 12 xx 10` <br/> `Delta U_(BC) = 100 - <a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a> = -20 J` <br/> As, `Delta U_(ABC) = Delta U_(AC)` <br/> `Delta U_(AB) + Delta U_(BC) = Delta Q_(AC) - Delta W_(AC)` <br/> `400 - 20 = Delta Q_(AC) - (2 xx 10^(4) xx 2 xx 10^(-3) + (1)/(2) xx 2 xx 10^(-3) xx 4 xx 10^(4))` <br/> `380 = Delta Q_(AC) - (40 + 40), Delta Q_(AC) = 380 + 80 = 460 J` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MTG_NEET_GID_PHY_XI_C08_E03_014_S01.png" width="80%"/></body></html>


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