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Figure shows two long parallel straight wires distance 5cm apart carrying currents `4A` and `10A` in opposite directions. Find the position of a point where the resultant magnetic field due to current in two wires in zero. |
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Answer» Correct Answer - `3*33cm` on the left hand side of wire X The resultant magnetic field will be zero at a point P on the left hand side of wire X. Let x be the distance of point P from wire x. Distance of point P from wire Y is (x+r). Magnetic field at P due to current in wire X is `B_1=(mu_0)/(4pi)(2I_1)/(x)=(10^-7xx2xx4)/(x)` acting perpendicular upwards. Magnetic field at P due to current in wire Y is `B_2=(mu_0)/(4pi)(2I_2)/((x+r))=(10^-7xx2xx10)/((x+5xx10^-2))` acting perpendicular downwards Resultant magnetic field will be zero at P if `B_1=B_2` or `(10^-7xx2xx4)/(x)=(10^-7xx2x10)/((x+5xx10^-2))` or `4/x=(10)/((x+5xx10^-2))` or `4x+20xx10^-2=10x` or `6x=20xx10^-2` or `x=(20xx10^-2)/(6)m=20/6cm=10/3cm=3*33cm` |
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