InterviewSolution
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Find each of the following products:(i) 3 × (-8) × 5(ii) 9 × (-3) × (-6)(iii) (-2) × 36 × (-5)(iv) (-2) × (-4) × (-6) × (-8) |
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Answer» (i) Given 3 × (-8) ×5 Here we have to find the product of given number. 3 × (-8) × 5 = 3 × (-8 × 5) =3 × -40 = -120 Since the product of two integers of opposite signs is equal to the additive inverse of the product of their absolute values. (ii) Given 9 × (-3) × (-6) Here we have to find the product of given number. 9 × (-3) × (-6) = 9 × (-3 × -6) [∵ the product of two integers of like signs is equal to the product of their absolute values.] =9 × +18 = +162 (iii) Given (-2) × 36 × (-5) Here we have to find the product of given number. (-2) × 36 × (-5) = (-2 × 36) × -5 [∵ the product of two integers of like signs is equal to the product of their absolute values.] =-72 × -5 = +360 (iv) Given (-2) × (-4) × (-6) × (-8) Here we have to find the product of given number. (-2) × (-4) × (-6) × (-8) = (-2 × -4) × (-6 × -8) [∵ the product of two integers of like signs is equal to the product of their absolute values.] =-8 × -48 = +384 |
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