Find out following (i) `V_(A)-V_(B)` (ii) `V_(B)-V_(C)` (iii) `V_(C)-V_(A)` (iv) `V_(D)-V_(C)` (v) `V_(A)-V_(D)` (vi) Arrange the order of potential for points A, B, C and D.

Find out following (i) `V_(A)-V_(B)` (ii) `V_(B)-V_(C)` (iii) `V_(C)-

1.	Find out following (i) `V_(A)-V_(B)` (ii) `V_(B)-V_(C)` (iii) `V_(C)-V_(A)` (iv) `V_(D)-V_(C)` (v) `V_(A)-V_(D)` (vi) Arrange the order of potential for points A, B, C and D.
Answer» (i) `\|DeltaV_(AB)\|=Ed=20xx2xx10^(-2)=0.4` So, `V_(A)-V_(B)=0.4 V` because in the direction of electric field potential always decreases. (ii) `\|DeltaV_(BC)\|=Ed=20xx2xx10^(-2)=0.4` so, `V_(B)-V_(C)=0.4 V` (iii) `\|DeltaV_(CA)\|=Ed=20xx4xx10^(-2)=0.8` so, `V_(C)-V_(A)=-0.8 V` because In the direction of electric field potential always decreases. (iv) `\|DeltaV_(DC)\|=Ed=20xx0=0` so, `V_(D)-V_(C)=0` because the effective distance D and C is zero. (v) `\|DeltaV_(AD)\|=Ed=20xx4xx10^(-2)=0.8` so, `V_(A)-V_(D)=0.8 V` because In the direction of electric field potential always decreases. (vi) The order of potential is : `V_(A) gt V_(B) gt V_(C)=V_(D)`.

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Find out following (i) `V_(A)-V_(B)` (ii) `V_(B)-V_(C)` (iii) `V_(C)-V_(A)` (iv) `V_(D)-V_(C)` (v) `V_(A)-V_(D)` (vi) Arrange the order of potential for points A, B, C and D.

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