Find p(0), p(1) and p(-2) for the following polynomials(i) p(x) = 10x

1.	Find p(0), p(1) and p(-2) for the following polynomials(i) p(x) = 10x – 4x2 – 3 (ii) p(y) = (y + 2)(y – 2)
Answer» (i) Given, polynomial is p(x) = 10x – 4x² – 3 On putting x = 0,1 and – 2, respectively in Eq. (i), we get p(0) = 10(0)-4(0)² -3 = 0-0-3 = -3 p(1) = 10 (1) - 4 1)² -3 = 10-4-3 = 10-7 = 3 and p(-2) =10 (-2)- 4 (-2)² – 3 = -20-4×4-3 =-20-16-3=-39 Hence, the values of p(0), p(1) and p(-2) are respectively, -3,3 and – 39. (ii) Given, polynomial is p(y) = (y+2)(y-2) On putting y =0,1 and -2, respectively in Eq. (i), we get p(0) =(0+2)(0-2)= -4 p(1) = (1 + 2)(1-2) = 3 x (-1) = -3 and p(-2) = (-2 + 2)(-2 -2) =0 (-4) = 0 Hence, the values of p(0),p(1) and p(-2) are respectively,-4,-3 and 0.

Find p(0), p(1) and p(-2) for the following polynomials(i) p(x) = 10x – 4x2 – 3 (ii) p(y) = (y + 2)(y – 2)

Answer»

(i) Given, polynomial is

p(x) = 10x – 4x² – 3

On putting x = 0,1 and – 2, respectively in Eq. (i),

we get p(0) = 10(0)-4(0)² -3

= 0-0-3

= -3

p(1) = 10 (1) - 4 1)² -3

= 10-4-3

= 10-7

= 3

and p(-2) =10 (-2)- 4 (-2)² – 3

= -20-4×4-3 =-20-16-3=-39

Hence, the values of p(0), p(1) and p(-2) are respectively, -3,3 and – 39.

(ii) Given, polynomial is p(y) = (y+2)(y-2)

On putting y =0,1 and -2, respectively in Eq. (i), we get p(0) =(0+2)(0-2)= -4

p(1) = (1 + 2)(1-2)

= 3 x (-1) = -3

and p(-2) = (-2 + 2)(-2 -2)

=0 (-4) = 0

Hence, the values of p(0),p(1) and p(-2) are respectively,-4,-3 and 0.