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Find the area of a triangle whose sides are 9 cm, 12 cm and 15 cm. |
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Answer» Let a, b and c are the sides of triangle and s is the semi-perimeter, then its area is given by: A = \(\sqrt{s(s-a)(s-b)(s-c)}\) where s = \(\frac{a+b+c}{2}\) [Heron’s Formula] a = 9, b = 12, c = 15 s = \(\frac{a+b+c}{2}\) = \(\frac{9+12+15}{2}\) = 18 A = \(\sqrt{18(18-9)(18-12)(18-15)}\) A = \(\sqrt{18 \times9 \times6 \times3}\) = 54 cm2 |
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