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Find the eccetricity of hyperbola through `(4,2)` whose centre is `(0.0)` length of transverse axis is 4 and transverse axis along x-axis. (a) `2` (b) `sqrt3` (c) `(sqrt3)/(2)` (d) `(2)/(sqrt3)`A. 2B. `(2)/(sqrt(3))`C. `(3)/(2)`D. `sqrt(3)` |
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Answer» Equation of hyperbola is given by `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` ` because ` Length of transverse axis = 2a = 4 ` therefore a=2` Thus, `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` is the equation of hyperbola ` because ` It passes through (4, 2). `therefore (16)/(4)-(4)/(b^(2))=1 rArr 4-(4)/(b^(2))=1 rArr b^(2)=(4)/(3) rArr b=(2)/(sqrt(3))` Now, eccentricity, `e=sqrt(1+(b^(2))/(a^(2)))=sqrt(1+((4)/(3))/(4))=sqrt(1+(1)/(3))=(2)/(sqrt(3))` |
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