1.

Find the equation of the circle whose centre is (2, – 5) and which passes through the point (3, 2).

Answer»

The general form of the equation of a circle is:

(x – h)2 + (y – k) 2 = r…..(1)

Where, (h, k) is the centre of the circle.

r = radius of the circle.

We are given with, centre = (2, – 5)

Or (h, k) = (2, – 5)

Find the radius of circle:

Since the circle passes through (3, 2), so it must satisfy the equation.

Put x = 3 and y = 2 in (1)

(3 – 2)2 + (2 + 5) 2 = r2

1 + 49 = r2

Or r2 = 50

Now,

Equation of circle is:

(x – 2)2 + (y + 5)2 = 50

Which is required equation.



Discussion

No Comment Found

Related InterviewSolutions