1.

Find the equation of the hyperbola whose conjugateaxis is 5 and the distance between the foci is 13.

Answer» Length of congugate axis of hyperbola ` = 5`
`=>2b = 5 =>b = 5/4`
`=>b^2 = 25/4->()`
Distance berween the foci ` =13`
`=>2ae = 13`
Squaring both sides,
`=>4a^2e^2 = 13^2`
`=>4a^2(1+b^2/a^2) = 169`
`=>a^2+b^2 = 169/4`
`=>a^2+25/4 = 169/4`
`=>a^2 = 169/4 -25/4 = 144/4`
`=>a^2 = 36`
Equation of a hyperbola is given by,
`x^2/a^2-y^2/b^2 = 1`
`:.` Equation of the given hyperbola,
`=>x^2/36-(4y^2)/25 = 1`


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