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Find the equation of the hyperbola whose conjugateaxis is 5 and the distance between the foci is 13. |
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Answer» Length of congugate axis of hyperbola ` = 5` `=>2b = 5 =>b = 5/4` `=>b^2 = 25/4->()` Distance berween the foci ` =13` `=>2ae = 13` Squaring both sides, `=>4a^2e^2 = 13^2` `=>4a^2(1+b^2/a^2) = 169` `=>a^2+b^2 = 169/4` `=>a^2+25/4 = 169/4` `=>a^2 = 169/4 -25/4 = 144/4` `=>a^2 = 36` Equation of a hyperbola is given by, `x^2/a^2-y^2/b^2 = 1` `:.` Equation of the given hyperbola, `=>x^2/36-(4y^2)/25 = 1` |
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