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Find the increase in the internal energy of a gas of mass 10 grams when it is heated from 300 K to 305 K.Given : Sv = 0.16 kcal/kg.K, J = 4186 J/kcal |
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Answer» Data : M = 10 grams = 10 × 10-3 kg, Sv = 0.16 kcal/kg.K, J = 4186 J/kcal Rise in the temperature of the gas, ∆T = 305 – 300 = 5K ∆E = J Sv M∆T = (4186)(0.16)(10 × 10-3) × (5) J = 33.49 J The increase in the internal energy of the gas, ∆E = 33.49 J |
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