InterviewSolution
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Find the interaction energy of two loops carrying currents `I_(1)` and `I_(2)` if both loops are shaped as circles of radii `a` and `b`, with `a lt lt b`. The loops centres are located at the same point and their planes from an angle `theta` between them. |
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Answer» We can think of the smaller coil as consituting a magnet of dipole moment, `p_(m) = pi a^(2) I_(1)` Its direction is normal to the loop and makes and angle `theta` with the direction of the magnetic field, due to the bigger loop. This magnetic field is, `B_(2) = (mu_(0) L_(2))/(2b)` The interactiion energy has the magnitude, `|W| = (mu_(0) I_(1) I_(2))/(2b) pi a^(2) cos theta` Its sign depends on the sense of the currents. |
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