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Find the magnifying power of a compound microscope whose objective has a focal power of 100D and eyepiece has a focal power of 16D when the object is placed at a distance of 1.1cm, from the objective. Assume that the final image is formed at the least distance of distinct vision, 25cm.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The magnifying power of a <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> microscope when the final image forms at the least distance <br/> of distinct vision `m=v_0/u [1+D/f_e]` To find `v_0`, ,<br/> Power of the objective `p_0=100D` Focal length of the objective `f=f_0=1/p_0=1/100 m=100/100 cm=1cm` <br/> `u=u_0=-1.1cm , v=v_0=?` <br/> FOra <a href="https://interviewquestions.tuteehub.com/tag/lens-1071845" style="font-weight:bold;" target="_blank" title="Click to know more about LENS">LENS</a> `1/f=1/v-1/u` <br/>`1/1=1/v_0-1/(1.1),1/v_0=1/1-1/1.1=0.1/1.1, v_0=1.1cm` <br/> Power of the eyepiece `p_e=16D` focal length of the eyepiece `f_e=1/p_e=1/16m=100/16 cm=6.25 cm`, <br/> Least distance of distinct vision `D=25cm` <br/> `therefore m=11/(-1.1) (1+25/6.25)=-<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> times 5=-50`</body></html>


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