1.

Find the maximum and the minimum values, if any, without using derivatives of the following functions :f(x) = 4x2 – 4x + 4 on R

Answer»

f(x) = 4x2 – 4x + 4 on R 

= 4x2 – 4x + 1 + 3 

= (2x – 1)2 + 3 

Since, 

(2x – 1)2 ≥ 0 

= (2x – 1)2 + 3 ≥ 3 

= f(x) ≥ f(\(\frac{1}{2}\))

Thus, the minimum value of f(x) is 3 at x = \(\frac{1}{2}\)

Since, 

f(x) can be made large. 

Therefore maximum value does not exist.



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