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Find the maximum and the minimum values, if any, without using derivatives of the following functions :f(x) = 4x2 – 4x + 4 on R |
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Answer» f(x) = 4x2 – 4x + 4 on R = 4x2 – 4x + 1 + 3 = (2x – 1)2 + 3 Since, (2x – 1)2 ≥ 0 = (2x – 1)2 + 3 ≥ 3 = f(x) ≥ f(\(\frac{1}{2}\)) Thus, the minimum value of f(x) is 3 at x = \(\frac{1}{2}\) Since, f(x) can be made large. Therefore maximum value does not exist. |
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