InterviewSolution
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InterviewSolution
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find the minimum attainable pressure of an ideal gs in the process `T = t_0 + prop V^2`, where `T_(0)n` and `alpha` are positive constants and (V) is the volume of one mole of gas. |
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Answer» Correct Answer - B `p = (R T)/(V)` `(n = 1)` or `p = (R) /(V) (T_0 + alpha V^2)` For minimum attainable pressure `(d p)/(d V) = 0 or (- R T_0)/(V^2) + alpha R = 0` or `V = sqrt((T_0)/(alpha))` At this volume we can see that `(d^2 p)/(d V^2)` is positive or (p) is minimum. From Eq. (i) `p_(min) = (R T_0)/(sqrt(T_0//alpha)) + alpha R sqrt(T _0 // prop)` = `2 R sqrt (alpha T_0)`. |
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