Find the molecular weight of the following compounds- a) Ca( HCO3)2 b) (NH4)3PO4 c) Fe2(SO4)3 [ Ca=40, H=1, C=12, O=16, N= 14, P=31, Fe=56, S=32 ]

Find the molecular weight of the following compounds- a) Ca( HCO3)2 b)

1.	Find the molecular weight of the following compounds- a) Ca( HCO3)2 b) (NH4)3PO4 c) Fe2(SO4)3 [ Ca=40, H=1, C=12, O=16, N= 14, P=31, Fe=56, S=32 ]
Answer» :-→ Molecular mass of Ca(HCO₃)₂ is 162 u .→ Molecular mass of (NH₄)₃PO₄ is 149 u→ Molecular mass of Fe₂(SO₄)₃ is 400 u .Explanation :-The atomic masses of elements are given as :-• Calcium = 40 u ; Hydrogen = 1 u• Carbon = 12 u ; Oxygen = 16 u• NITROGEN = 14 u ; Phosphorus = 31 u• Iron = 56 u ; Sulphur = 32 u______________________________Number (a) :-The given compound is Ca(HCO₃)₂ i.e. "Calcium bi-carbonate" .Molecular weight will be :-= 40 + (1 + 12 + 16 × 3)2= 40 + (13 + 48)2= 40 + (61)2= 40 + 122= 162 uNumber (b) :-The given compound is (NH₄)₃PO₄ i.e. "Ammonium PHOSPHATE" .Molecular weight will be :-= (14 + 1 × 4)3 + 31 + 16 × 4= (14 + 4)3 + 31 + 64= (18)3 + 95= 54 + 95= 149 uNumber (c) :-The given compound is Fe₂(SO₄)₃ i.e. "Ferric Sulphate" .Molecular weight will be :-= 56 × 2 + (32 + 16 × 4)3= 112 + (32 + 64)3= 112 + (96)3= 112 + 288= 400 u