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Find the number of ways in which 4 people E, F, G, H, A, C can be seated at a round table, such that E and F must always sit together.(a) 32(b) 290(c) 124(d) 48I have been asked this question by my school principal while I was bunking the class.Origin of the question is Counting in section Counting of Discrete Mathematics

Answer»

Correct option is (d) 48

The BEST I can explain: E and F can sit together in all ARRANGEMENTS in 2! Ways. Now, the arrangement of the 5 PEOPLE in a circle can be done in(5 – 1)! or 24 ways. Therefore, the total number of ways will be 24 x 2 = 48.



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