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Find the number of ways in which four distinct balls can be kept into two identical boxes so that no box remains empty. |
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Answer» Correct Answer - 7 4 distinct balls can be divided into two nonempty groups as 1,3 or 2,2 Sine boxes are identical, number of ways of division and distibution are same `therefore` Number of ways `=(4!)/(1!3!)+(4)/(2!2!2!)=4+3=7`. |
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