Find the oxidation number of sulphur in the following compounds: `H_(2)S,H_(2)SO_(4),S_(2)O_(4)^(2-),S_(2)O_(8)^(2-),HSO_(3)^(ө)`.

Find the oxidation number of sulphur in the following compounds: `H_(2

1.	Find the oxidation number of sulphur in the following compounds: `H_(2)S,H_(2)SO_(4),S_(2)O_(4)^(2-),S_(2)O_(8)^(2-),HSO_(3)^(ө)`.
Answer» Correct Answer - B::C::D For neutral molecule, sum of oxidation number of all the atoms is equal to zero and for a charged species equals to the charge on the ion. In `H_(2)S`, the oxidation number of `H` is `+1`, `H_(2)S=2+x-0` `x= -2` Oxidation number of `S= -2` In `H_(2)SO_(4)`, the oxidation numoer of `H` is `+1`, for `O` it is `H_(2)SO_(4)= 2+x-8= 0` `x=+6` Oxidation number of `S` is `+6`. In `S_(2)O_(4)^(2-)`, oxidation number of `O` is `-2`, `S_(2)O_(4)^(2-): , 2x-8= -2` `x=3` `:.` oxidation numbers of `S` is `+3` In `S_(2)O_(8)^(2-)`, we have one peroxide bond, therefore, for two oxygens atom, oxidation number is `-1` and for the order six oxygen atoms, the oxidation number is `-2`. or oxidation number of `S=6`. In `HSO_(3)^(ө)`, oxidation number for `H` is `+1` and oxidation number of `O` is `-2` `1+`(oxidation number of S) `+3(-2)= -1` or oxidation number of `S= +4` It may be noted that sulphur is in different oxidation number states in different compounds. The is true in the next example also in which `Cl` is in different oxidation state.

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Find the oxidation number of sulphur in the following compounds: `H_(2)S,H_(2)SO_(4),S_(2)O_(4)^(2-),S_(2)O_(8)^(2-),HSO_(3)^(ө)`.

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