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Find the point on the curve y = x2+3x+4 at which the tangent passes through the origin. |
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Answer» If tangent is pass through origin it means that equation of tangent is y = mx Let us suppose that tangent is made at point (x1, y1) y1 = x12 + 3x1 + 4 …(1) m : dy/dx = 2x+3 m at (x1, y1) = 2x1 + 3 Equation of tangent : y1 = (2x1 + 3)x1 …(2) On comparing eq(1) and eq(2) x12 + 3x1 + 4 = (2x1 + 3)x1 x12 – 4 = 0 ⇒ x1 = 2 and -2 At x1 = 2, y1 = 14 At x1 = -2, y1 = 2 So, required points are (2, 14) and (-2, 2) |
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