1.

Find the point on the curve y = x2+3x+4 at which the tangent passes through the origin.

Answer»

If tangent is pass through origin it means that equation of tangent is y = mx

Let us suppose that tangent is made at point (x1, y1)

y1 = x12 + 3x1 + 4 …(1)

m : dy/dx = 2x+3

m at (x1, y1) = 2x1 + 3

Equation of tangent : y1 = (2x1 + 3)x1 …(2)

On comparing eq(1) and eq(2)

x12 + 3x1 + 4 = (2x1 + 3)x1

x12 – 4 = 0

⇒ x1 = 2 and -2

At x1 = 2, y1 = 14

At x1 = -2, y1 = 2

So, required points are (2, 14) and (-2, 2)



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