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Find the roots of the following quadratic (if they exist) by the method of completing the square.\(2x^2+x-4=0\) |
Answer» We have to make the quadratic equation a perfect square if possible or sum of perfect square with a constant. \((a+b)^2=a^2+2ab+b^2\) \(2x^2+x-4=0\) ⇒ x2 + x/2 – 2 = 0 ⇒ x2 + 2 × 1/4 × x + (1/4)2 - (1/4)2 – 2 = 0 ⇒ (x + 1/4)2 = 33/16 ⇒ x + 1/4 = √33/4 \(\Rightarrow x=\frac{\sqrt{33}-1}{4},\frac{-\sqrt{33}-1{}}{4}\) |
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