Find the time period of another pendulum of length equal to half of it

1.	Find the time period of another pendulum of length equal to half of it at the same place.
Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/pendulum-1149901" style="font-weight:bold;" target="_blank" title="Click to know more about PENDULUM">PENDULUM</a> is given by <br/> `T= 2pisqrt((l)/(g)) ….(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) :. G= 4pi^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(l)/(T^(2))` i.e., `(l)/(T_(1)^(2))= (l_(2))/(T_(2)^(2)) implies (1.0)/(2^(2))= (0.50)/(T_(2)^(2))` or `T_(2)^(2)= (0.50)/(1.01) xx 4= 2 ` <br/> `:. T_(2)= sqrt(2)= 1.414s`</body></html>

Find the time period of another pendulum of length equal to half of it at the same place.