Find the time taken for height of water level to fall from 'h' to 'h'in a vessel, if water comes out from a small hole at the bottom

Find the time taken for height of water level to fall from 'h' to 'h'i

1.	Find the time taken for height of water level to fall from 'h' to 'h'in a vessel, if water comes out from a small hole at the bottom
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :From <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of continity for an incompressible liquid `Av^(1)=asqrt(2gh)` (or) `v^(1)=((a)/(A))sqrt(2gh)` <br/>where `v^(1)` is the <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of descendence of the <a href="https://interviewquestions.tuteehub.com/tag/level-1072714" style="font-weight:bold;" target="_blank" title="Click to know more about LEVEL">LEVEL</a> of free surface. So, `v^(1)` can be <a href="https://interviewquestions.tuteehub.com/tag/written-732709" style="font-weight:bold;" target="_blank" title="Click to know more about WRITTEN">WRITTEN</a> as: `V^(1)=(-dh)/(dt)` <br/>`therefore (-dh)/(dt)=((a)/(A))sqrt(2gh)` (or) `overset(h^(1))underset(h)int(dh)/(sqrt(h))=-((a)/(A))sqrt(2g)overset(t)underset(t=0)intdt` <br/>`therefore 2(sqrt(h^(1)-sqrt(h))) =-((a)/(A))(sqrt(2g))t` (or)`t=(2A)/(asqrt(2g))(sqrt(h^(1))-sqrt(h))prop t`</body></html>