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Find the total current in the circuits shown in Fig. , , and . Each diode used is ideal |
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Answer» In Fig. , both the diode `D_(1)` and `D_(2)` are forward biased. Their effective resistance in current is zero. Current in circuit is `I=3.0/10=0.3A` In Fig., diode `D_(1)` is forward bias and diode `D_(2)` is reverse biased. Resistance due to `D_(2)` will be infinity to the current flowing through it. So Current in the circuit, `I=(3.0)/(10+oo)=0` In Fig. , both the diode `D_(1)` and `D_(2)` are forward biased, Their effective resistance in the circuit is zero. So Current in the circuit is `I=3.0/10=0.3A` In Fig. , diode `D_(1)` is forward biased and diode `D_(2)` is reverse biased. No current will flow through `D_(2)` as its resistance become infinity being reverse biased. The resistance to current by `D_(1)` is zero. The current in the circuit is due to `D_(1)` only, which is given by `I=3.0/10=0.3A` |
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